Question 120
Four OSPFv2 routers join a new shared Ethernet network and simultaneously elect DR and BDR. Router A has priority 120 and ID 1.1.1.1; B priority 40 ID 9.9.9.9; C priority 40 ID 8.8.8.8; D priority 0 ID 10.10.10.10. Which TWO statements identify the correct election outcomes? (Select TWO.)
Explanation
Correct Answers
After identifying the DR, eligible B and C have equal priority 40, so the higher router ID 9.9.9.9 wins the BDR tie break. The priority-zero router cannot become DR or BDR.
An OSPF broadcast-network DR election considers nonzero interface priority first and router ID as tie breaker. A's priority 120 exceeds 40 and zero, so it is the preferred DR in this simultaneous election.
Incorrect Answers
OSPF DR/BDR election does not produce two simultaneous DRs for the same multiaccess segment. Router ID breaks the equal-priority tie between B and C after higher-priority A is selected DR.
An OSPFv2 priority of zero makes an interface ineligible for DR or BDR election. A router ID can break a tie only among eligible candidates with equal priority.
After eligible highest-priority A becomes DR, B and C both have priority 40. The higher router ID, B at 9.9.9.9, wins the remaining BDR position.





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