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134 Questions & Answers

Last Update: Oct 06, 2026

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Anthropic CCA-F Practice Test 10

Question 90

An agent's PreToolUse hook returns malformed JSON and Claude Code proceeds inconsistently. What is the safest repair?

  1. Delete the policy hook and rely on user prompts
  2. Treat a hook’s zero exit code as proof that its JSON decision payload has the required fields
  3. Validate hook output against the documented response schema and test the configured failure behavior
  4. Treat every malformed response as an allow without documentation

Explanation

Correct Answer

C:

A PreToolUse hook that emits malformed JSON is not reliably communicating the approval or denial decision expected by Claude Code. The team must use the current documented hook response schema, ensure all required types and fields are correct, and test how the configured environment treats missing, invalid or timed-out responses. For high-risk operations, choose a documented blocking or escalation policy rather than assuming silent allow. Log the actual hook error without leaking sensitive input and confirm a forbidden synthetic operation is stopped. This distinguishes process exit status from parseable policy output and makes the security boundary observable.

Incorrect Answers

A:

Removing a failing PreToolUse policy hook and relying solely on a natural-language rule would leave risky execution requests without the intended machine-enforced check. The malformed JSON problem is an output-contract defect, not proof that authorization should be abandoned. Validate hook responses against the documented fields and exit semantics, test both allowed and blocked operations, and define what happens if the hook errors. A prompt reminder can supplement the guard but cannot replace its execution-time decision. The appropriate repair strengthens the hook interface rather than disabling it.

B:

A process can exit normally while returning malformed, incomplete or semantically inconsistent policy data. The host must validate the documented hook response schema and know how failure or absent decisions affect enforcement. Relying on exit status alone can bypass a required PreToolUse permission gate. Confirm both transport success and correctly typed output fields, then apply the configured fail-closed or escalation behavior when the payload violates the contract.

D:

Accepting every malformed hook response as permission to proceed would convert a policy integration bug into an allow-by-default bypass. The model could then perform the very file edit the guard was installed to restrict, while operators see only an apparently harmless formatting failure. Test parsing failures and return a documented denial or escalation decision for protected actions; leave lower-risk behavior consistent with explicit policy. Unknown response shape is not evidence that the underlying request is safe or authorized.

Question 91

A repository uses different allowed commands for unit-test runners and deployment writers. How should hooks avoid overblocking harmless reads?

  1. Permit every command executed by a familiar agent
  2. Match rules on tool identity and operation arguments, applying deny conditions only to targeted actions
  3. Block every Bash invocation whenever deployment scripts exist
  4. Turn off hook logging to reduce noise

Explanation

Correct Answer

B:

Scoped conditions retain read access while preventing forbidden destructive or publishing operations. Treat read, edit, shell and network write operations as distinct risk classes. A tool-name-only restriction can overblock safe reads while missing risky writes elsewhere. Inspect the actual operation and canonical arguments and deny only targeted effects under the relevant repository policy. Confirm the matching rule covers alternate command forms and nested invocations. Broad rules needlessly prevent safe inspections and tests. Agent identity alone cannot confer arbitrary privileges.

Incorrect Answers

A:

Recognizing a familiar worker is not authorization for arbitrary commands that worker can issue. The same agent may legitimately read test fixtures yet lack permission to run deployment scripts or mutate protected resources. A hook that trusts the identity alone cannot distinguish these side effects. Enforcement should examine the actual requested tool and its arguments against policy, then allow safe operations while rejecting prohibited writes regardless of who proposed them.

C:

Blocking every Bash invocation because deployment scripts exist would prevent harmless test, inspection and diagnostic commands. The presence of a risky script somewhere in the repository is not evidence that a particular invocation will execute it. A well-scoped guard differentiates command behavior, target paths and write effects, and should use stronger sandbox boundaries where command parsing is unreliable. Broad indiscriminate blocking increases false positives without establishing that all possible write routes are controlled.

D:

Disabling hook logging removes the context needed to audit which tool and arguments were allowed or denied. It does not make the underlying permission decision more selective, and it can conceal attempted bypasses through alternative shell syntax. The proper remedy is a narrowly scoped policy with safe, redacted audit metadata. Keep enough trace evidence to investigate unexpected denials and dangerous attempts without copying credentials or sensitive tool input into open logs.

Question 92

A Claude Code hook takes 45 seconds to query a remote policy server on every file read. What design reduces latency without removing the policy?

  1. Remove the policy check from all tools
  2. Move cheap local allow checks ahead of bounded, cached remote policy checks
  3. Increase timeout indefinitely
  4. Treat a cached allow result as valid regardless of the policy version or its expiry

Explanation

Correct Answer

B:

Classify low-risk file reads using inexpensive local policy checks before contacting a slow remote service. Cache eligible decisions only within a bounded validity window and bind entries to the actual resource, actor and policy version, so a rule change or revoked grant cannot inherit an old allow. Requests that are uncertain or capable of sensitive writes should still reach the appropriate stronger check under a finite timeout and documented failure policy. This design cuts repeated network latency without declaring the guard irrelevant; it also provides measurable cache-hit, timeout and misclassification evidence for QA. A performance optimization cannot waive the policy itself.

Incorrect Answers

A:

Removing the remote policy step from every tool would certainly reduce latency, but it would also discard the control that determines whether protected operations are permitted. The performance problem is repeated expensive evaluation even for harmless file reads, not proof that no rule is needed. Introduce cheap local checks for clearly allowed cases and scope any cache to the actual principal, resource and policy revision. Escalate uncertain or high-impact actions to the required authoritative check rather than silently bypass the guard.

C:

Allowing the hook to wait indefinitely for a remote policy server moves a fixed forty-five-second delay into an unbounded stall and can prevent normal repository inspections from finishing. Waiting longer does not guarantee a safe approval or a correct result. Use bounded timeouts, fast local allow decisions for known low-risk operations and appropriately scoped caching when policy permits. If a mandatory high-risk check cannot complete, follow an explicit denial or escalation rule rather than leaving the agent hanging or silently granting access.

D:

Caching can reduce remote policy-server latency, but an old allow decision may apply to a different rule set, principal or resource. A high-impact action still needs evidence that the cached authorization covers the current request and is within its validity window. Put cheap local checks first, then use properly scoped and versioned cache entries or bounded remote checks. Reusing an expired allowance without context can silently bypass newer restrictions.

Question 93

A compliance hook needs to approve only reads of approved test data, not customer production records. Which information must drive its decision?

  1. Decide access from the requested tool's name alone, assuming every Read operation in a repository targets nonproduction data
  2. Whether the agent says it is doing compliance work
  3. Canonical file path, operation type and applicable access policy
  4. Accept a read when the raw path string starts with the test-fixtures directory name, without resolving its actual destination

Explanation

Correct Answer

C:

The target resource and requested access determine authorization, not the user's descriptive label. Protect against path traversal and aliases by evaluating resolved targets. A data-read guard must inspect canonical path, intended operation and classification rules, not just a friendly file name. Production records stay prohibited when the worker is only authorized for test fixtures. Keep the record of denied attempts without exposing protected file contents. Self-described intent is weaker than an enforced resource rule. Prompt length does not grant file permissions.

Incorrect Answers

A:

Read is a broad operation category, not a sensitivity classification of the target resource. The same tool can open approved fixtures or customer production records, and aliases or symlinks can lead a seemingly harmless path outside the intended directory. The hook must bind canonical target path, effective operation and the caller's access scope to the actual policy. Relying only on the tool name would permit forbidden customer records whenever an agent invokes a familiar read interface.

B:

A statement that the agent is performing compliance work describes its assignment, not the sensitivity of the file it wants to open. A worker can sincerely intend to inspect test data yet submit a path that resolves into production customer records. The hook needs to examine the caller's actual scoped authority and the resolved file object before executing the read. Otherwise the model's self-description becomes an access-control bypass, and the audit cannot establish why a protected source was disclosed.

D:

Textual prefix checks appear inexpensive, but a symlink or path traversal component can cause a superficially approved path to resolve to customer production records. The hook must distinguish operation type and effective resource identity using canonical paths and applicable access policy. Only the allowed test-data scope should be readable. A raw prefix check is weaker than host-enforced authorization and may admit a prohibited file even when the command looks harmless.

Question 94

A subagent inherits a tool hook that masks personally identifiable information from tool output. Where should redaction occur to prevent the model reading raw identifiers?

  1. In an unrelated local Git commit hook
  2. By asking the model to promise not to mention names
  3. At the output boundary before sensitive result text is supplied to the model
  4. Only when rendering the final user message

Explanation

Correct Answer

C:

The output boundary is the critical control: inspect the actual tool payload and apply the configured PII removal or masking before the content is supplied to Claude or a delegated subagent. Preserve enough non-sensitive identifiers and provenance for the authorized task, and record a redacted audit event without copying the protected values. This prevents the model from using raw identifiers in intermediate reasoning, follow-up tool calls or final text. Test nested data and alternate encodings, since masking only the visible final answer would be too late.

Incorrect Answers

A:

A Git commit hook fires only for relevant version-control actions, not necessarily when a subagent reads a tool result. Sensitive identifiers might have entered the model context long before any commit is attempted, and some sessions never commit. Redaction must occur at the tool-result delivery boundary where the sensitive text would first become visible to the assistant. Git policy may provide additional repository safeguards but cannot substitute for output sanitization.

B:

A model can still receive and reason over raw identifiers even if instructed not to repeat them. Such a promise offers no hard guarantee against accidental disclosure, copied traces or prompt injection from external data. A trusted host component should filter or deny the sensitive fields before the result is sent into the subagent's context. Preventing exposure is stronger than asking the model to self-censor after reading it.

D:

Redacting only the final message leaves raw data inside the model's earlier context and possibly in intermediate calls or logs. An agent could have used the identifier in a search or copied it into another tool result before the display filter runs. Sanitize at ingestion, not merely presentation; final-output checks can be a second defense but do not solve this exposure. The question expressly requires preventing the model from reading the raw value.

Question 95

A hook records tool activity in a world-readable log with full environment variables. What specific flaw has been introduced?

  1. The audit channel itself now exposes credentials and secrets
  2. The extra audit entries will necessarily cause duplicate event processing even if the logs are never read by automation
  3. The unrestricted hook log makes the provider's tool_result response invalid JSON by default
  4. Rotate and compress the logs hourly while retaining full environment-variable values and world-readable permissions

Explanation

Correct Answer

A:

Observability should capture decision metadata while protecting sensitive request fields and environment values. Log allow/deny rationale, tool category and redacted identifiers where needed. World-readable hook logs containing environment variables become a credential disclosure path. Record minimal event metadata and redacted diagnostics with restricted log access rather than copying secrets into the audit channel. Apply least privilege and retention controls to the audit destination. Formatting is unrelated to secret leakage from audit files. Logging volume is secondary to unauthorized secret access.

Incorrect Answers

B:

Verbose logs may complicate storage or later analysis, but merely recording additional events does not prove that any downstream job will process a callback twice. The stem gives a concrete security exposure: the file is world-readable and includes full environment-variable values. The audit channel can disclose credentials to unauthorized users even if no event is duplicated. A secure design must restrict access and redact secret-bearing fields before persistence, rather than diagnosing an unobserved execution-replay bug.

C:

A local audit log and a tool response are distinct output channels unless an implementation explicitly mixes them. Writing sensitive environment fields to a separate world-readable log does not, by itself, change the provider's tool_result schema. The direct risk is that users outside the authorized audience can read credentials or tokens persisted in the audit file. Fix log permissions, minimize captured fields and avoid copying environment variables; diagnose JSON response corruption only if there is evidence of output-channel mixing.

D:

Rotation limits retention and disk consumption but does not remove secrets from records while they exist. Any account able to read the files can extract captured environment variables before compression, and archived copies may remain accessible afterward. The defect is that sensitive values enter a broadly readable audit channel at all. Correct it with redaction, minimal event metadata, restricted log permissions and an appropriate retention policy; rotation is only an additional operational control.

Question 96

A PreToolUse policy declines a proposed request to edit a protected settings file. What should the agent do next?

  1. Report that configuration was updated successfully
  2. Delete the policy file with a separate tool
  3. Repeat the same blocked write with a cosmetic command change
  4. Preserve the denial as actual state and propose an authorized alternative or escalation

Explanation

Correct Answer

D:

A PreToolUse denial is an observed policy outcome, so the next assistant step should preserve it and avoid claiming the file changed. Explain which protected settings operation was blocked, then suggest an allowed read-only diagnosis, a user-approved alternative, or escalation to the accountable administrator. Do not retry the same protected effect through an equivalent interface. Keeping the denial in the audit trail also prevents later agents from treating the absent update as completed, and supports safe resumption if authorization changes through a separate approved process.

Incorrect Answers

A:

Reporting a successful settings update contradicts the observed PreToolUse denial. The protected file should remain unchanged because the host rejected the proposed edit. An assistant may explain what it intended and which permission was missing, but must not claim a configuration state it did not observe. Preserve the denial and request approved access or propose a non-mutating workaround rather than manufacturing a completion receipt.

B:

Deleting the policy file with a different tool is a direct attempt to bypass the protection that just denied an edit. The underlying resource and operation remain sensitive regardless of which command runner reaches them. Strong host controls should prevent equivalent effects through shell or alternate editing interfaces. The model cannot grant itself authority by removing the mechanism that enforces permission; escalate the legitimate request instead.

C:

Cosmetic changes to a blocked command do not resolve the permission issue. A retry using a synonym, alternate path spelling or different tool can be an unauthorized bypass rather than a correction. The agent should distinguish a remediable malformed argument from an explicit protected-path denial. Here the latter applies, so repeated attempts must stop unless an authorized actor actually changes the permissions or the requested target.

Question 97

A team needs the same pre-execution guard to apply in both interactive Claude Code use and CI runners. What is a sound deployment approach?

  1. Disable hooks in CI because it is automated
  2. Commit project-scoped hook configuration and verify CI loads it in an isolated test
  3. Describe the rule only in a chat message
  4. Rely on one engineer's personal dotfiles

Explanation

Correct Answer

B:

A project-scoped hook configuration checked into the repository can supply a shared policy for interactive developers and CI jobs. Verify that each execution environment actually reads that configuration, has the required hook executable, and enforces the intended deny behavior against a protected test path. Keep credentials outside tracked files and apply least-privilege CI identities separately. Common configuration reduces drift but does not prove identical behavior until tested. A successful dry run should include both an allowed read and a prohibited mutation so that a missing hook is detectable.

Incorrect Answers

A:

CI automation is often highly privileged and can publish artifacts unattended, so disabling a required pre-execution guard there would remove the control from a risky environment. The fact that a run is noninteractive does not make its tool calls safe by definition. Use a supported project configuration and test that the hook loads under the actual CI identity, checking both permitted and denied operations. Treat missing hook installation as a test failure, not an invisible exception.

C:

A chat instruction may tell an agent which operations are forbidden, but it does not install executable hook logic into a CI runner or define machine-readable approval behavior. CI often starts with a fresh context, so the old conversation might not even be present. Commit the supported project policy files and test the installed hook rather than relying on a prior natural-language promise.

D:

One engineer's local dotfiles do not necessarily exist on a clean CI worker or another developer's machine. A guard that works only on that laptop will disappear when the same repository is built in isolation, creating inconsistent enforcement. Put the shared nonsecret configuration in an appropriate project-controlled location and verify it in the actual execution environment. Personal settings can supplement policy but cannot establish fleet-wide coverage.

Question 98

A Claude Code Bash test command actually starts and exits with status 1, returning a diagnostic error. A team wants a hook to capture that failed invocation and its error for audit without claiming the test passed. Which hook event fits?

  1. PostToolUse for successful tool operations, recording a pass even if the test returned an error
  2. SessionEnd, inferring each failed command from a session-wide completion summary
  3. PreCompact, because context reduction supplies the exact failed command result
  4. PostToolUseFailure for the executed failed tool call, including its tool input and reported error

Explanation

Correct Answer

D:

PostToolUseFailure applies after a tool execution fails and includes the attempted tool name and input, a tool-use identifier and error information. In this scenario Bash really ran and reported a nonzero outcome, so the event can preserve that diagnostic evidence without inventing success. It is materially different from input-schema rejections or permission denials that occur before execution; those do not necessarily fire this event. Record a safe redacted command summary and the observed error, retaining the failed outcome for subsequent retries or escalation.

Incorrect Answers

A:

PostToolUse fires after a tool completes successfully, so it is not the appropriate failure event for the Bash command that actually exited with a nonzero status. Recording a PASS under that event would misrepresent the observed test result. The team needs a hook whose input includes the attempted tool call and its failure payload. This is distinct from permission or schema rejection before tool execution, which has different event behavior.

B:

A session ending is not equivalent to recording the exact failed test invocation at the time it occurs. By the end of the session, several commands might have run, succeeded or failed, and a summary could omit relevant error details. The requested audit record needs the actual command, associated tool-use ID and exit diagnostic from this specific attempt. Use the per-tool failure event rather than reconstructing outcomes from a later session-level description.

C:

PreCompact prepares or transforms conversation context; it is not a reliable source for the immediate outcome of an executed test command. Context reduction may omit or summarize older observations and does not itself establish what Bash returned. The team should capture the actual failed tool event and its error fields before compaction. A continuation summary can reference that record later, but should not replace the recorded test failure with inferred text.

Question 99

A guard hook on an expensive code-generation workflow sometimes exceeds its timeout. Which policy is most defensible for high-risk publication tools?

  1. Fail closed or require explicit escalation when the mandatory validation cannot finish
  2. Assume timeout means approval
  3. Downgrade a mandatory policy gate to a warning when its remote service times out
  4. Send release notifications anyway

Explanation

Correct Answer

A:

The guard's timeout leaves the mandatory publication policy undecided. Because the tool can release material externally, the executor should block the side effect or use an explicitly authorized escalation path rather than treat absent validation as permission. Record which check timed out, the artifact and policy scope involved, and permit resumption only after the required evaluation is actually completed. A time limit on a validator is operationally necessary but cannot transform an unknown policy result into a PASS. Optional or low-risk actions might have different fallback policies, but this stem specifically defines the gate as mandatory for high-risk publishing.

Incorrect Answers

B:

A timeout establishes only that the hook did not finish its decision within the allotted interval. It does not say the proposed publication passed security review, so permitting it would defeat the guard whenever its server is slow. Maintain a denied or pending state and preserve a safe error record. The authorized owner can retry the check or escalate under policy, but neither the model's confidence nor elapsed time can produce the missing positive approval.

C:

A timeout is an unknown decision, not an explicit authorization. Automatically treating a required check as advisory would allow sensitive actions without the evidence the workflow mandates. The host should stop or escalate under the documented policy rather than assume the request is safe. Optional checks may have different fallback rules, but the scenario specifically identifies a mandatory gate whose unavailable state must not be silently weakened.

D:

A release notification after a timed-out mandatory guard could tell stakeholders that an artifact was safely published while the executor lacks any verified policy decision. Notifications are downstream status reports, not a replacement for access or release authorization. Do not perform the high-risk publication until the required check succeeds or an authorized exception is recorded, and do not announce completion until the provider confirms the action. Keep timeout and pending review clearly distinct from success.

Question 100

A team uses a PreToolUse hook to guard only tool name Write; a model instead edits files through Bash redirection. What caused the bypass?

  1. Too many read-only tools were enabled
  2. The model's temperature was too high
  3. Add examples in CLAUDE.md saying not to redirect shell output, while keeping the policy restricted to the Write tool
  4. The policy matched a tool label rather than all equivalent filesystem write effects

Explanation

Correct Answer

D:

The protection was attached only to a tool label, Write, while the filesystem could also be modified through Bash shell redirection. The policy therefore controlled one interface rather than the underlying effect of changing protected files. Secure execution must cover all equivalent write paths, check effective target paths and permissions, and use sandbox or filesystem enforcement where command parsing alone is unreliable. Test both direct edit and shell-based mutation attempts against a protected fixture. Adding a prose reminder to CLAUDE.md may guide behavior but does not remove the alternate executable route.

Incorrect Answers

A:

Read-only tools did not cause the protected file mutation. The bypass happened because the guard watched one named write interface while Bash could achieve an equivalent filesystem effect through redirection. Removing additional read tools would not stop that shell path. The host needs authorization at the actual resource or effect boundary, or comprehensive checks across all write-capable tools with an appropriate sandbox. Tool counts and permissions are different dimensions of the problem.

B:

Changing the model's sampling temperature could alter how often it happens to choose Bash rather than Write, but it cannot close an execution-policy gap. A lower-temperature model can still produce an unauthorized redirection command, and external text can encourage it. Enforcement belongs in the host or sandbox so that equivalent writes are denied regardless of which syntactic tool the model proposes. Determinism in text generation is not proof of resource authorization.

C:

A repository instruction can encourage good behavior but does not eliminate an alternative filesystem mutation path. Bash redirection, edit commands and other write-capable tools may still reach the protected resource while a hook watches only the Write label. The actual enforcement must cover equivalent effects at the command or filesystem boundary. Examples can be useful supplemental training, but a model can ignore them or issue a mistaken shell command, so they cannot repair an incomplete allow/deny policy by themselves.


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